length and vowel count in string

Basic Programs

If Else based Programs

Loop Based Programs

Array Based Programs

String Programs

Function Programs

Pointers Programs

Structure & File Handling Programs

Data Structure Programs

String based programs

Find length of string and count vowel in string

#include<stdio.h>
#include<conio.h>
void main()
{
int i=0,count=0;
char str[80];
printf("enter the string");
gets(str);
while(str[i]!=NULL)
{
if(str[i]=='a'||str[i]=='e'||str[i]=='i'||str[i]=='o'||str[i]=='u')
{
count++;
}
i++;
}
printf("string length=%d no of vowels=%d",i,count);
}

C Program to reverse string and check if it is palindrome

#include<stdio.h>
#include<conio.h>
void main()
{
int i=0,lastIndex=0,count=0,flag=0;
char str[80],str1[80];
printf("enter the string");
gets(str);
while(str[i]!=NULL)
{
 i++;
}
lastIndex=i-1;
i=0;
while(str[i]!=NULL)
{
 str1[i]=str[lastIndex];
 if(str[i]!=str1[i])
 {
  flag=1;
  }
 i++; 
 lastIndex--;
}
str1[i]=NULL;
printf("reverse string is\n");
puts(str1);
if(flag==0)
printf("the given string is palindrome");
else
printf("not palindrome");

}

C program to check substring in the given string

#include<conio.h>
#include<stdio.h>
void main()
{
int i=0,j=0;
char str[50],substr[50];
clrscr();
printf("Enter the string : ");
gets(str);
printf("Enter substring : ");
gets(substr);
while(str[i]!=NULL && substr[j]!=NULL)
{
if(str[i]!=substr[j])
{
i++;
j=0;
}
else
{
j++;
i++;
}
}
if(substr[j]==NULL)
printf("substring Found");
else
printf("Not found");
}

C Program to replace a word with another in string

#include<stdio.h>
#include<conio.h>
void main()
{
int i=0,count=0;
char str[80];
printf("enter the string\n");
gets(str);
while(str[i]!=NULL) 
{
if(str[i]=='a'&& str[i+1]=='n' && str[i+2]=='d')//replace and with the
{
str[i]='t;
str[i+1]='h';
str[i+2]='e';
i=i+2;
}
i++;
}
printf("the change string is ");
puts(str);
}

C Program to count four letter word in given string

#include<conio.h>
#include<stdio.h>
void main()
{
int i=0,j=0, k=0;
char d[50], c[50];
clrscr();
printf("Enter the string : ");
gets(d);
for(i=0;d[i]!=NULL;i++)
{
j=0;
while(d[i]!=32 && d[i]!=NULL)
{
j++;
i++;
}
if(d[i]==NULL)
i--;
if(j==4)
{
k=k+1;
}
}
printf("Four letter word are : %d", k);
}